Re: Challenge  

  By: be on April 7, 2011, 11:33 p.m.

Kann jemand helfen?

Ihre Lösung sah perfekt aus, bis dass der erste Buchstabe des ersten Wortes fehlte (jedenfalls bei dem String, der hier am Server ankam).
Bitte tippen Sie es nochmal ganz ein.
Wenn es nicht klappt, mailen Sie mir direkt Ihre Lösung.
MfG Be

Re: Challenge  

  By: friiky on April 8, 2011, 8:58 a.m.

Guten Tag,

jetzt ging es.

Danke sehr.


Re: Challenge  

  By: haegarq on April 14, 2011, 2:33 p.m.

Tach auch,

jetzt ging es durch. Problem bestand in der richtigen Auflösung des Alphabets.

Nochmals vielen Dank.


Re: Challenge  

  By: bobthemaster on May 10, 2011, 2:55 a.m.

Hey Leute,

ich habe den Text geloest und er gibt auch komplett Sinn auf Englisch. Doch leider ist die Loesung irgendwie falsch. Meine Vermutung ist eigentlich, dass ich irgendein Satzzeichen falsch gesetzt habe, bin mir aber nicht sicher.
Bitte um Rueckmeldung, um den Fehler zu beheben.


Re: Challenge  

  By: be on May 10, 2011, 5:04 p.m.

ich habe den Text geloest und er gibt auch komplett Sinn auf Englisch. Doch leider ist die Loesung irgendwie falsch.

bitte schauen Sie sich die Kommentare zu dieser Aufgabe im Forum an. Da hier nicht das Standardalphabet genutzt wurde, sondern ein 62-Alphabet, das sich aus 3 Teilalphabeten zusammensetzt, kann es z.B. sein, man erhält einen sinnvollen Text, in dem aber noch die Groß-/Kleinschreibung falsch ist.

Re: Challenge  

  By: bobthemaster on May 10, 2011, 11:33 p.m.

@be: vielen dank fuer den tipp, ich war noch viel zu sehr bei dem einzelnen, dass ich das komplett verpeilt habe.
Und sorry fuer den unintellektuellen post…..

Re: Challenge  

  By: Veselovský on July 29, 2011, 11:14 p.m.

It is not so clever challenge…
It can be solved in more than one way
2010 - 1999 = 11 (if today is/was 2010) and 2011 - 2000 = 11 (if today is 2011)
AD (Anno Domini) can equally well be replaced with CE (Christian Era)
then "script kiddie" or "Script kiddie" or "Script Kiddie" … there is no logic explanation that just one of these three should be grammatically correct
If you count all the possibilities then the number is bigger then allowed trials
I have 7 trials left and see no sense in trying again…

Re: Challenge  

  By: be on July 30, 2011, 9:34 p.m.

If you count all the possibilities then the number is bigger then allowed trials

That's not true. First the text makes sense as an English text and is spelled correctly.
Secondly we have a 62-alphabet consisting of 3 part-alphabets which must be arranged in the right order.
But as you solved it in the meantime by yourself you can maybe give the community another hint.

Re: Challenge  

  By: Veselovský on Aug. 12, 2011, 1:30 p.m.

I was solving it as a monoalphabetic substitution not as a Caesar cipher, that's why I got more possibilities.
Difference between a monoalphabetic substitution and a Caesar cipher:
if alphabet is ABC as an example
this: A->B,B->C,C->A is possible for Caesar cipher
this: A->A,B->C,C->B is not possible for Caesar cipher

but both examples above are possible for a monoalphabetic substitution
in Caesar cipher the key is ordered exactly same as alphabet only is shifted by some positions to the left or right
in a monoalphabetic substitution key can be any permutation of alphabet

Re: Challenge  

  By: fretty on Aug. 12, 2011, 4:27 p.m.

The caesar cipher was invented first and then the monoalphabetic substitution cipher was invented as a more general process.

Essentially monoalphabetic substititons on the usual 26 letter alphabet are in one to one correspondance with bijections Z_26 -> Z_26.

The Caesar ciphers correspond to such bijections of the form n -> n+k, for a fixed integer k.

There are what are known as Affine ciphers that correspond to the more general affine maps n -> an + k, for fixed integers a,k such that a is coprime to 26 (to make the inverse exist).

Re: Challenge  

  By: concordbjf on Aug. 26, 2011, 3:30 a.m.

Two Hints if your (incorrect) solution is in English:

Hint #1: When others say the solution should be in "normal english text", this means (in part) that capitalization rules should be followed in the plain text solution (more or less - there's two adjacent words where capitalization, or lack thereof, is debatable - but you have 15 tries!).

Hint #2: Read your english solution and make sure it make sense…Example: while "42 + 23 = 11" is a properly formed mathematical equation (syntactically speaking), it is incorrect, i.e. it doesn't make sense.

Re: Challenge  

  By: fretty on Aug. 26, 2011, 9:13 a.m.

I don't see the "ambiguity" that people seem to be having trouble with.

Re: Challenge  

  By: effort2break on Dec. 29, 2011, 8:09 p.m.

I've wasted my chances by futile attempts to unlock the answer and am left with only 5 trials . Can some one please help…. I have checked the numbers and upper and lower case characters and the special characters as well…… still [HTML_REMOVED] … please help [HTML_REMOVED]

Re: Challenge  

  By: effort2break on Dec. 30, 2011, 8:16 p.m.

The missing idea which helped me to solve it: An alphabet is a set, where the elements have to stay in a given order: So its always A B C …, but never B A C !!!

Re: Challenge  

  By: M1cHa3l on April 10, 2012, 1:21 a.m.

I'm having the same problem as the people before me. I have deciphered a readable english text but it still tells me that it is wrong.

I have read all your clues but I can't seem to find the correct solution :/

I have 3 trials left :P

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