Challenge "Factorization Cipher — Part 1" ¶
By: admin on Oct. 17, 2011, 6:42 p.m.
With the help of 7 pairs of plaintext-ciphertext you have to find out how this factorization cipher works and then decrypt a ciphertext.
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By: admin on Oct. 17, 2011, 6:42 p.m.
With the help of 7 pairs of plaintext-ciphertext you have to find out how this factorization cipher works and then decrypt a ciphertext.
Read more...
By: bgr on June 24, 2013, 11:53 a.m.
I think I have not understood what to do.
The factorization itself is no issue, but I have no clue what to do with the result. Is the challenge itself to link the result of the factorization somehow to letters?
Bernhard
By: FivePrime on March 21, 2014, 4:35 p.m.
I used a couple of calculators on the internet before I got ones that could handle the number which you gave as cipher text.
If you are having difficulty, try a few different online calculators, you'll soon get one that does the work properly and allows you to see the real pattern.
By: cfreuden on Jan. 11, 2016, 6:45 p.m.
Look at the 7 examples.
They are the prime source of information.
Look at the differences and similarities of the plaintexts and try to see how the correspond with their factorizations.
2 of the 7 expamples contain a blank space in the clear text. But according to the explanation on page 4 the blanks have to be ignored.
Is this true also for the expamples?
By: Veselovský on Jan. 11, 2016, 10:48 p.m.
…blanks have to be ignored. Is this true also for the expamples?
Yes, of course, same for examples as for challenge. Spaces/blanks are removed before encryption.
By: Veselovský on Nov. 7, 2020, midnight
Unless my algorithm is incorrect, why not let 4539620 = CAR instead
of the therefore unnecessarily inflated 168919260200?
"CAR" is not the only example for which a ciphertext is provided. Just the next one "A CAR" should provide enough clues why the particular number and not any other.
By: Veselovský on Nov. 7, 2020, 10:45 a.m.
Ahhh… Because the Solution contains No duplicate letters
(and I don't think that is too much of a clue…)
the "A CAR" example is unnecessary for
Part 1, as is "ABBA"… I happened to
look at CAR, CAB and I AM, only…And now that I see the complication of duplicates,
I do not see why 402271083010688000 is
necessary when 5538336400 gives
exactly the same "A CAR"…
Algorithm dependent…And 4539620 =
CAR stands…
All examples as they are provided in the challenge are relevant, ignoring some of them may lead to incorrect results.
Following your logic, why should be 5538336400 equivalent of "ACAR" and not of "RCRA"?
By: admin on Nov. 25, 2020, 3:03 p.m.
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By: tryone144 on Nov. 25, 2020, 3:22 p.m.
Hi Ken,
please keep the discussion objective. As you have already identified:
Unless my algorithm is incorrect …
The autor @Veselovský has already pointed out all the hints to understand the algorithm at hand. You just found another algorithm that happens to work for this specific challenge.