On Nov. 24, 2023, 10:06 p.m.
Is there something unusual about the plaintext? When I search for the XOR wheels, I expect an IoC about 15% above random, but the best I a find is about 11%, a…
Posts
Topics
On Nov. 24, 2023, 10:06 p.m.
Is there something unusual about the plaintext? When I search for the XOR wheels, I expect an IoC about 15% above random, but the best I a find is about 11%, a…
On Nov. 22, 2023, 8:02 p.m.
How much of the plaintext is numbers? I ask because I see Z and X more often than I expect, and I need to know if I have to adjust my statistics.
On Oct. 18, 2023, 12:20 a.m.
It looks at though this challenge needs to be brute-forced, and if we can believe that the keylengths are less than 10, the workload is 2^80.
On Oct. 16, 2023, 3:53 p.m.
*length *4272
Edit by admin: Thanks, typo fixed
On Sept. 12, 2023, 8:28 p.m.
If it matters, there is a spelling error in one of the plaintexts for this challenge, and that error has now been corrected in the Project Gutenberg file. So t…
On Sept. 6, 2023, 2:09 p.m.
Hi, there.
The instructions ask for a correctly cased plaintext. Are we to include spaces and punctuation? The ciphertext file is in UTF-8; should we submit a…
On Aug. 28, 2023, 9:16 p.m.
What is the "characteristic" that you use to compare to a corpus? I'm only getting a 1.3% difference using that one statistic that will not be named. Is that e…
On Aug. 27, 2023, 8:37 p.m.
You only think you made a mistake. If you swap the ciphertexts, you can get the same plaintexts with a different key. It's the glory of XOR.
On Aug. 24, 2023, 4:31 a.m.
I noticed something about this challenge. The documentation says that for this model, there are only 960 unique substitution alphabets, but with the wheel sett…
On Aug. 19, 2023, 2:05 a.m.
Yes. No.
Yes, Mark Stamp should know about it. No, I haven't solved it. And the bug is irrelevant to Stamp's attack.
Thanks a lot.
On Aug. 17, 2023, 4:19 p.m.
Hi,
There is also a typo on page 12 of the Function Description PDF: The caption to the diagram is missing "IV:".
I can only reconcile the description to the…
On Aug. 8, 2023, 9:35 p.m.
And finally, I would like to ask how the bits for generating the rotations in AR() are chosen. From Álvarez et al., they say bits 1..5 for the first rotation, …
On Aug. 8, 2023, 9:29 p.m.
Also,
w[1] = ((w[1] & 0xfffffffe) << t) | (w[1] >> (31 - t)) | (w[1] & 0x1);
should be
w[1] = ((w[1] & 0xfffffffe) << t) | ((w[1] >> (31 - t)) & 0xfffffffe) | (w[1] & 0x1);
in four place…
On Aug. 8, 2023, 8:55 p.m.
I found a bug in the C code for this challenge. In the AR box, for the rotations that preserve the leftmost bit,
w[0] = (w[1] << t) | ((w[0] & 0x7fffffff) >> (31 - t)) | (w[0] & 0x80000000…<>
On Aug. 7, 2023, 4:30 p.m.
Can somone please confirm that the given information about the key is used by the C code in this way:
./Sigaba ..........01234 .......... ABCDEZYXWV4.... 1 WW…