Forum

Forum Profile

D3d4lu5

Statistics

16

Posts

0

Topics

Recent posts (View all)
Re: Challenge

 On Nov. 15, 2019, 5:35 p.m.

I guess there is an issue with the cipher texts that belong to the Vigenère Cipher.

It is neither a classical Vigenère nor an autokey cipher.

Neverthele…

Re: Challenge

 On Nov. 14, 2019, 9:39 p.m.

There are some cipher texts that look pretty weird.

For example no 105 is:

"qddqfmsqdaqoukvqccusudujcqbycwmvxmrbhoilethereadertobecomegenuinelyabsorbedi…

Re: Challenge

 On Aug. 25, 2019, 10:21 p.m.

The kind of solution should be changed.

It's really annoying to spend most of your time finding the right punctuation.

Re: Challenge

 On July 16, 2019, 5:54 p.m.

It was an encoding issue due to the import in eclipse.

That's why the Baudot translation did not work properly with a slightly different translation of the…

Re: Challenge

 On July 16, 2019, 12:17 a.m.

As I said, meanwhile I have fully recovered the plaintext, but the system does not accept my solution.

And if I understand "You should enter only the 6 digi…

Re: Challenge

 On July 15, 2019, 10:50 p.m.

Hello George,

thanks for your reply. I did a mistake with the wheel sizes and can now decode the complete ciphertext.

But I already tried the correct 6-d…

Re: Challenge

 On July 15, 2019, 6:41 a.m.

Something seems to be wrong.

I can't completely recover the plaintext.

Could you please check if the ciphertext can be translated correctly with the java…

Re: Challenge

 On May 21, 2019, 10:57 p.m.

The challenge description says "3. Reconstitute a 41-character key from the resulting table, inserting the ^ character at the same position it occupied in the …

Re: Challenge

 On March 10, 2019, 4:48 p.m.

I already solved this challenge, but I could not reconstruct the entire plaintext.

Do I have to test the ring and stecker positions too?

Re: Challenge

 On July 31, 2017, 6:58 p.m.

"…replace every asterisk by a space and enjoy a comfortable reading." (not for entering the solution)

As I said, in my opinion the description is misleading…

Re: Challenge

 On July 29, 2017, 6:28 p.m.

The plaintext alphabet consists of the following 28 characters:
ABCDEFGHIJKLMNOPQRSTUVWXYZ*.

Find the 5th sentence counting from the end and provide…

Re: Challenge

 On July 26, 2017, 4:56 p.m.

Do I need special computational power to solve this challenge?

My program works quite well for "CMEA 1" and finds the key in a few minutes.

But for this…

Re: Challenge

 On July 10, 2017, 9:30 p.m.

I had to dump 0.5 TB (!) to finally find the private key.

Although I knew the openssl implementation, for safety's sake my self-written program scanned for …

Re: Challenge

 On July 6, 2017, 6:39 p.m.

Mit freundlicher Unterstützung von be wird meine Lösung nun vom System akzeptiert.

Allerdings scheint nicht ganz klar zu sein, was das Problem gewesen ist. …

Re: Challenge

 On June 20, 2017, 9:58 p.m.

Ich habe wie in der Aufgabenstellung beschrieben den Gesamtschlüssel als Konkatenation der beiden Teilschlüssel ohne Leerzeichen im Hexformat mit Minuskeln und…


Currently 18 guests and 0 members are online.
Powered by the CrypTool project
Contact | Privacy | Imprint
© 2009-2022 MysteryTwister team