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ExAstris

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Re: Challenge "Enigma Part 1"

 On July 17, 2023, 1:10 a.m.

True, I understand, no problem.

Re: Challenge "Enigma Part 1"

 On July 15, 2023, 1:45 a.m.

Hello, hallo,

still struggling with this one. I tried quite a few implementations, without success.

"Not straightforward" is crystal clear to me, but my own …

Re: Challenge ""The Road" — Part 2"

 On June 29, 2023, 4:48 p.m.

OK, thanks newton,

so I am missing something.

Re: Challenge ""The Road" — Part 2"

 On June 29, 2023, 4:42 p.m.

Hello,

in mtc3-gutgesell-07-theroad-02-en.pdf, there is a hint that says:

"Hints for this modification can be found in the last plaintext of the 1st part (2 …

Re: Challenge

 On May 26, 2021, 9:07 p.m.

Just FYI,

my solution was correct. It looks like there are at least 4 valid solutions.

Re: Challenge

 On May 25, 2021, 9:12 p.m.

Hello all,

I got the plaintext by using a "choices" form as the -ks argument, but this "choices" form is not accepted as a valid solution.

I don't see ho…

Re: Challenge

 On May 15, 2021, 1:29 a.m.

Hello,

I found the words and the sentence. I think I got the format right from the PDF, yet I am told it is the wrong answer. Is there a subtlety in the for…

Re: Challenge

 On May 7, 2021, 6:03 p.m.

Well,

what do you know, after conjecturing that there might be another sequence matching the given one, I did find one, which is the correct one for this ch…

Re: Challenge

 On May 7, 2021, 5:50 p.m.

Hello,

strangely, I entered the 5 digits separated by spaces as requested,
but my answer, which I think is correct, was rejected.

Either my input format…

Re: Challenge

 On June 29, 2018, 12:15 a.m.

Hello all,

I read Jomandi's useful tips, and I have a few questions.
I am new at this, so bear with me, I am probably missing something really simple.

1…

Re: Challenge

 On June 21, 2018, 3:11 p.m.

Yes, without additional knowledge, there is an obvious order to try.
In my previous note, positions were starting at zero (as in my program), but they are pro…

Re: Challenge

 On June 21, 2018, 2:07 a.m.

I have not solved it, so don't take my word for it!

N has 80 numbers, you must find 8 numbers out of the 80 that will sum up to c. The concatenation of the …

Re: Challenge

 On June 14, 2018, 10:42 p.m.

Thank you Anna,

it is very helpful, as I was trying to use the binary number instead of the positions.

I appreciate your support!

Re: Challenge

 On June 13, 2018, 3:12 a.m.

I used ellipses to indicate that I had more significant digits than 5,
my problem is that I had more than a thousand digits, without success.
I am surprised,…

Re: Challenge

 On June 13, 2018, 3:04 a.m.

Hi,

I understand (I think) how to get c from N. After finding c, since n/10=8, we get 8 bits.
What I don't understand is how (which system/method) is the c…


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